5/x-2+3/x+2=x/x^2-4

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Solution for 5/x-2+3/x+2=x/x^2-4 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

5/x+3/x-2+2 = x/(x^2)-4 // - x/(x^2)-4

5/x+3/x-(x/(x^2))-2+2+4 = 0

5/x+3/x-x^-1-2+2+4 = 0

7*x^-1 = -4 // : 7

x^-1 = -4/7

-1 < 0

1/(x^1) = -4/7 // * x^1

1 = -4/7*x^1 // : -4/7

-7/4 = x^1

x = -7/4

x = -7/4

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